Substitute x = 2458 into x y z = 2 2458 y z = 2 y z = 0458 y = z 0458 Substitute x = 2458 into xyz = 4 (2458)yz = 4 yz = 1627 y = 1627/z y = 1627/z = z 0458 1627 = z^2 0458zz^2 0458z 1627 = 0 z^2 0458z 1627 = 0 z = (0458 / sqrt ((0458)^2 4*1627))/2 z = (0458 / sqrt (6298))/2X^ {2}\left (yz\right)xy^ {2}yzz^ {2}=0 x 2 ( − y − z) x y 2 − y z z 2 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, yz for b, and y^ {2}z^ {2}yz for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x(iii) In the expression 4x y – 4xyz z , the terms are 4x 2 y 2, – 4x 2 y 2 z 2 and z 2 Coefficient of x 2 y 2 in the term 4x 2 y 2 is 4 Coefficient of x 2 y 2 z 2 in the term – 4x 2 y 2 z 2 is – 4
If Xy Yz Zx 1 Prove That X 1 X 2 Y 1 Y 2 Z 1 Z 2 4 Xyz 1 X 2 1 Y 2 1 Youtube
